Calculus help with derivatives please

Find the derivative of this function:(x - 7x sqrt(x)) / sqrt(x)
in two ways

A) By using Quotient Rule
B) By simplifying first

A) derivative
= [(1 - 7(3/2)x^(1/2))sqrt(x) - (x - 7x sqrt(x))/(2sqrt(x))]/x
= 1/sqrt(x) - 21/2 - 1/(2sqrt(x)) + 7/2
= 1/(2sqrt(x)) - 7

B) (x - 7x sqrt(x)) / sqrt(x) = sqrt(x) - 7x
So, the derivative = 1/(2sqrt(x)) - 7

(1 - [7sqrtx+7x(1/2)sqrtx^(-1/2)])sqrtx - (1/2)sqrtx^(-1/2)) / x

That's the derivative of the top times the bottom minus the derivative of the bottom times the top all divided by the bottom squared