Evaluate the integral 35dx / 35 + e^x

I cannot figure out how to do this. any help would be appreciated :)

Hint:
(35+e^x-e^x)/(35 + e^x)
= 1 - e^x/(35+e^x)

So, the integral becomes
integral of 1 - e^x/(35+e^x) dx
= x - ln(35+e^x) + c