Find (in rectangular form) the two values of sqrt(-8+6i)

[From: ] [author: ] [Date: 12-06-07] [Hit: ]

a)Find (in rectangular form) the two values of sqrt(-8+6i)
Solve the equation z^2 +sqrt(32)iz-6i=0.
Thanks for your help

-8+6i = 1 + 6i + 9i^2 = (1+3i)^2 ---> sqrt (-8+6i) = 1 + 3i or -1 - 3i

2/
solve by the quadratic formula

keywords: rectangular,two,form,sqrt,of,values,in,Find,the,Find (in rectangular form) the two values of sqrt(-8+6i)