What are the foci of the graph (y^2)/(110)-(x^2)/(34)=1

ok I got -0,89 but im not sure because I graphed it in every thing but im just not sure about my answer

a =sqrt(110)
b =sqrt(34)
c^2 = a^2 + b^2
c^2 = 110 + 34
c = 12

the center is at (0,0)
vertex is at (0,sqrt(110)) and (0,-sqrt(110))
the foci is at (0,12) and (0,-12)