The vertices of a triangle are A(-4,0), B(2,0) and C(0,6). Let Msub1, Msub2 and Msub3 be the midpoints of sides AB, BC and AC, respectively. Let Hsub1, Hsub2 and Hsub3 be the feet of the altitudes on sides AB, BC and AC, respectively.
Find the point P at which the three altitudes intersect.
Find the point P at which the three altitudes intersect.
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To find point P where the three altitudes intersect
- since one of the vertex (C) is on the y axis, and leg AB lies on the x axis- one of the altitude is the y axis
y=0
all you need to do is
- write the slope of segment AC
since the altitude AH2 is _|_ to segment AC, its slope m = -1/ slope of line AC
once you've found the slope of the altitude BH3, use it to write equation for altitude AH3
point P is where AH3 and y axis intersect.
- since one of the vertex (C) is on the y axis, and leg AB lies on the x axis- one of the altitude is the y axis
y=0
all you need to do is
- write the slope of segment AC
since the altitude AH2 is _|_ to segment AC, its slope m = -1/ slope of line AC
once you've found the slope of the altitude BH3, use it to write equation for altitude AH3
point P is where AH3 and y axis intersect.