How do you solve i^73

[From: ] [author: ] [Date: 12-09-28] [Hit: ]

so divide 73 by four and take the remainder.73/4 = 18 remainder 1. so you go to your little list and go to 1. so the answer is i.......

i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
i^5 = i
i^6 = -1

theres as pattern... every fourth power the cycle of i, -1, -i, 1 repeats. so divide 73 by four and take the remainder.

73/4 = 18 remainder 1. so you go to your little list and go to 1. so the answer is i.