A patient is administered a a dose of 50 mg of a drug. If the body naturally disposes of 4% of the drug every hour, how quickly will the amount of the drug be changing7 hours after ingestion?
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There will be 50(0.96)^7 grams left after 7 hours. The rate of change will then be 4% of this amount or -50(0.96)^7 *0.04 grams per hour.
This could be modeled using calculus but it is not clear to me that you are looking for such a solution.
A(t) = 50(0.96)^t
A '(t) = 50(0.96)^t *ln 0.96
Now substitute 7 in for t to get your answer.
This could be modeled using calculus but it is not clear to me that you are looking for such a solution.
A(t) = 50(0.96)^t
A '(t) = 50(0.96)^t *ln 0.96
Now substitute 7 in for t to get your answer.