y=(x-6)^2 + 3
Can someone show me how to do this step by step pls? Thanks!
Can someone show me how to do this step by step pls? Thanks!
-
In vertex form, the equation is:
y = 1(x-6)^2 + 3
y = a(x-h)^2 + k
where (h, k) is the vertex. Using this info, the vertex is (6, 3). Since a is positive, the parabola opens upward, and therefore, (6, 3) is the minimum.
y = 1(x-6)^2 + 3
y = a(x-h)^2 + k
where (h, k) is the vertex. Using this info, the vertex is (6, 3). Since a is positive, the parabola opens upward, and therefore, (6, 3) is the minimum.
-
minimum turning point at (6,3)