What Would The X-Intercepts Of This Be

Were doing rational functions in class, and I don't exactly know how to do this.

3x^2 - 7x

I can common factor out the x, which would change the equation to x (3x - 7), so would the x intercepts then be 0 and 7/3 or am I wrong?

Do I use quadratic formula? Thank you in advance :)

You're correct!

If you use the quadratic formula, you'll get the same answers!

3*x^2 - 7*x = 0

a = 3, b = - 7, c = 0

b^2 - 4*a*c = ) - 7)^2 - 4*3*0 = 49

x1 = ( - ( - 7) + sqrt(49))/(2*3) = (7 + 7)/6 = 14/3 = 7/3

x2 = (7 - 7)/6 = 0

Set it equal to zero and factor out an x

3x^2-7x=0
x(3x-7)=0

x=0, x= 7/3

So yes you're right.

The x - int are when that function = 0
So, 3x^2 - 7x = 0
x(3x - 7) = 0

Your answers are right