I need to find the integral of the fuction (e^(-x+2))^2. Please people help!

∫ (e^(2 - x))² dx
∫ e^(4 - 2x) dx

Let u = 4 - 2x
du = -2 dx
-1/2 du = dx

-1/2 ∫ e^u du
-1/2 e^u + C
-1/2 e^(4 - 2x) + C, or
-1/2 (e^(2 - x))² + C