Having trouble with an integration by parts problem.

Integral of [(xe^2x)/((1+2x)^2)] dx

I know this is an integration by parts problem but I keep getting stuck when trying to find my u and dv. I always get an incredibly complex du. Please help.

Let u = xe^2x, dv = 1/((1+2x)^2) dx
u' = e^2x + 2xe^2x = e^2x * (1 + 2x)
v = -0.5/(1 + 2x)

The integral is then
(-0.5xe^(2x) / (1+2x)) + 0.5integral{(e^2x)(1 + 2x)/(1 + 2x) dx}
So the terms in the last integral cancel out and you can integrate it easily