Algebra question how do i solve this

rewrite the expression without using the absolute value |x+8| if x<-8

-x-8

Put the negative in front of x to make it positive and subtract 8. The answer will be positive.

x < - 8
=> x + 8 < 0
=> x + 8 = - p (say), where p > 0
Now | x + 8 | = | - p | = p = - (x + 8), where x < - 8