2x-3/x=1, solve for x.?

2x-3/x=1, solve for x.

As you have it written, you would have to multiply all by x giving you:

2x^2 - 3 = x

then you move the x over giving you:

2x^2 - x - 3 = 0

Now it is a quadratic so you have to factorise giving you:

(2x - 3)(x + 1) = 0

Now you know that one of the brackets must equal 0 so you will end up with 2 answers:

2x - 3 = 0
2x = 3
x = 1.5

and

x + 1 = 0
x = -1

x = 1.5 and x = -1

Do these steps:
2x-3=x (Multiply x with 1)
2x=x+3 (Bring 3 to right)
2x-x=3 (Bring x to left)
x=3 (Solve for x)

(2x-3)/x=1
2x - 3 = x
2x - x = 3
x = 3

If your equation is meant to be 2x - 3/x = 1, then
(2x^2 - 3)/x = 1
2x^2 - 3 = x
2x^2 - x - 3 = 0
x = [1 ± √(1 + 25)]/4 = (1 ± 5)/4
Therefore
x_1 = - 1
x_2 = 3/2

x=3
see step by step solution:
http://symbolab.com/solver/equation-calc...

hope this helps

2x-3/x=1
(2x^2)/x -3/x = 1
(2x^2-3)/x =1
(2x^2-3)=x
(2x^2-x-3)=0
X=3 or x=-2

As given , MUST be read as :-

2x - (3/x) = 1

2x ² - 3 = x

2x ² - x - 3 = 0

(2x - 3)(x + 1) = 0

x = 3/2 , x = - 1