Can you answer the following questions:
1.) When you multiply a complex number by its conjugate, the answer will always be _____.
2.) to find the conjugate of a complex number, you need to ______.
3.
I dont understand. I know the rule is subtracting two negatives equal to adding but i dont get whats the logic behind that?
Can anyone explain please.-Think about subtracting negatives. If you are sub
Assuming that f: A --> B and g: B --> CProve If g o f is one to one then g may or may not be one to one.-Let g(x) = x^2 and f(x) = sqrt(x).Then let A = all real numbers, B = C = all nonnegative real n
If possible, solve the system of linear equations in 3 variables.
a - 4b + 3c = 2
-a - 2b + 5c = 9
a + 2b + c = 6-(1) a - 4b + 3c = 2
(2) -a - 2b + 5c = 9
(3)a + 2b + c = 6
add:
(2)-a - 2b + 5c = 9
(
type an expression using x as the variable-X is a number.
3X is three times a number
2 + 3X is two more than three times a number.-2+3x
three times a number is 3x
two more than that is 2+3x-3x +2-3x
Okay so I need to know the numbers for every single percent up to 100% Like this:
1%= (number)
2%= (number)
3%= (number)
....and so on.
Im just kinda curious. Kbye.-That doesnt really make any se
the lines x + y = 0 and x + y = 4/3 are tangent to the graph of y = F(x), where F is an antiderivative of -x^2. Find F-f (x) = -x^2
F(x) = -(1/3)x^3 + C
eqn of tangent is given by
y = F(a) + f (a
y=sin(cosx)
y=cos(cosx)
y=tan(sinx)
y=log(cosx){log to the base e}-use a function plotter like:http://www.onlinefunctiongrapher.com/
links to your graphs:
sin(cos(x)) :http://www.onlinefunctiongrapher
Just a little puzzle. Feel free to share any of your own.
We start with a simple
a = b
Multiply both sides by a
a^2 = ab
Add a^2 to each side
2a^2 = a^2 + ab
Minus 2ab from each side
2a^2 - 2ab = a^2
-4x-9y-z=11
-8x-6y-2z=-2
6x+9y+z=-7
&
-x+y+z=-1
-x+5y-19z=-29
7x-6y-12z=0
& one more...
5x-6y+5z=13
10x-12y+10z=23
-15x+18y-15z=-37-x = 2, y = -2, z = -1
x - 6z = -6
y - 5x = -7
or
x = 6t - 6
y =
To find f + g, add the expressions for f(x) and g(x). Its as simple as that. (2x - 3) + (x^2 - 6x).-You know what f(x) is and you know what g(x) is. All we have to do is all them together.
2x - 3 +
Youre given a function f(x)=(sqrtx^2 +6x)
1) Solve the equation: f(x)=3x-2
2) Solve the inequality: f^2(x)
Results: 1 - x=2; 2 -x E(-6;0)
How should I solve these? In a previous exercise I was given
3y+(y/x)=x
=> y + (y/3x) = x/3 ............stanadard form
this is a linear first order differential equation, ( of the form y + P(x)y = Q(x) )
here P(x) = 1/3x and Q(x) = x/3
Integrating factor( I
