the gradient given in 3/5
thanks in advance!-y=ln(e^x +e^-x)
differentiate ...
y = [1/(e^x +e^-x)] [e^x - e^-x]
y = [e^x - e^-x]/[e^x + e^-x]
gradient given in 3/5
3/5 = [e^x - e^-x]/[e^x + e^-x
a parabola satisfies the following conditions
vertex on x-y-2=0
focus on x+y-2=0
with vertical directrix; and passes through the point (9,7)
find the equation(s) of the parabola(s) write them in stand
Determine the numbers of terms n in each geometric series
a1=-3, r=3, Sn= -363
just one problem so that i can understand-Sn = {a(r^n - 1)} / (r - 1)
-363 = (-3) (3^n -1) / (3 - 1)
(-363) 2 = (-3)
A 2x2x2 cube is removed from each corner of an 8x8x8 cube. What fraction of the original cube remains? express your answer as a common fraction.
Please and thank you!
And if you could please show me
How to find the reaction force on B in below frameworks?
http://oi56.tinypic.com/a13f6e.jpg-If B is a level surface,
then reaction of Bar AB, at b = w cos(60)=w/2
and same for other bar.
78-Just divide 70/90 you get .77777777777777777. Multiply that by 100 to get percentage-i believe a 70 is a C-
and a 90 is a A-.-I think its a C.-i believe that is a C+
Dear Aunt Sally is now in her fifties, but is still working and putting away money for retirement.It is nearly the deadline for her to file her taxes, and she will have to pay.Right now, she owes $1,0
I need help answering this question!
Dana and Cathy are playing tennis. Given that the probability of Dana winning at least 1 out of 2 games is 0.3, what is the probability she will win at least 1 ou
the number of elements |K(g)| of the conjugacy class K(g) of the element g divides the order |G| of the group G.-If you are familiar with the terminology of group actions this is a consequence of a st
2.) Simplify sin2 θ(1 – csc2 θ).This math totally confuses me and I take cyber school so I dont have anyone to help me. Thanks.-1. tan2 θ(1 – cot2 θ)
= tan2 θ – tan2θ *cot2 θ
= tan2 θ – 1
2. sin2 θ
x^3 + x^2 - x =0
help me solve this please!
any help would be greatly appreciated!-x^3 + x^2 - x =0
x(x^2 + x -1) = 0
for the equation x^2 + x -1
x = [-b±√(b^2-ac)]/2a
x = [-1±√(1^2-4X1X-1)]/2X1
x =
Im not sure what to do when simplifying this, so working out would be good-Lets rewrite it so that it doesnt look as confusing.
3(x + 2)²(x - 5)² + 2(x + 2)(x - 5)³
Since there are multiple (x + 2)
13
STEP 1:Set up the proportion of the percent = amount-to-base ratio.
n/100=
STEP 2:Cross multiply to remove the fractions.
100 ×= n ×= n ×
STEP 3: Solve for n.
n =%-n250
-----X.-----= 75
100
