Please HELP me!!! Can u someone provide me with a step by step solution. I'll give 10 pts to best answer! Plea

Please HELP me!!! Can u someone provide me with a step by step solution. I'll give 10 pts to best answer! Please please please help


An object is initially moving in the positive x direction and a constant acceleration in the negative x direction is applied to the object. Due to the acceleration, the object stops after undergoing a displacement of 23 meters. If the object's initial velocity was increased by a factor of 4.4, with the same acceleration, what would now be the object's displacement in meters when it stops? (Hint: use an appropriate constant acceleration equation and then apply the concept of proportions.)

consider the equation

vf^2=v0^2 + 2ad

vf=final velocity, since the objects come to rest, vf=0 in both cases
v0=initial velocity
a=acceleration; in these cases, a will be negative since it is in the direction opposite motion
d=distance traveled

so we have

0=v0^2-2ad or d=v0^2/2a

this shows that the distance traveled varies as the square of the initial velocity; if you increase the initial velocity by a factor of 4.4, then the distance traveled will increase by a factor of 4.4^2

so the distance traveled in the second case will be 23 m x 4.4^2

I could but don't feel like it right now...maybe later.