Can you solve this Physics problem

I'm confused over what equations to use and why so if you could explain the steps to me, thanks.

"A truck falls off a cliff. If the cliff is 33.5 meters high, how much time does it take for the truck to reach the ground."

Could you explain how to solve for the velocity? Thanks.

So make a data table of all the elements of the problem:

Velocity initial: 0m/s
Velocity final: ????
Acceleration of gravity: 9.8m/s
Time: ????
Distance: 33.5m

Final velocity formula:
Vf = SQRT((Vi^2) + (2*A*D)
Vf = SQRT((0^2) + (2*9.8*33.5)
Vf = SQRT(656.6)
Vf = 25.62m/s

Time Formula:
t = (Vf - Vi) / (A)
t = (25.62 / 9.8)
t = 2.62 seconds

Velocity is given by v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is acceleration due to gravity, and s is the displacement, which in this case is the height in metres.

We will assume that the truck has no vertical velocity at the beginning of the question, so u = 0.

Now we have a = 9.8 ms^-2, s = 33.5 m, and we are trying to find v.

v^2 = u^2 + 2as
= 0 + 2*9.8*33.5
= 656.6
v = sqrt(656.6)
v = 25.624 ms^-1

So the instantaneous velocity when the truck hits the ground is 25.6 ms^-1.

Time is more difficult to find, and we will use the equation:
s = ut + 1/2at^2

We have to rearrange for t. First we will factorise the right hand side and take t out of the brackets:
s = t(u + 1/2at)

Divide the left hand side by the brackets:
t = s/(u+1/2at)

And now we have to move the t back over to the other side, so we will multiply both sides by t.
t^2 = s/(u+1/2a)

Now we square root both sides to find the formula for t.
t = sqrt(s/(u+1/2a))

Now we may solve for t.

t = sqrt(33.5/(0+1/2*9.8))
= sqrt(33.5/4.9)
=sqrt(6.8367)
=2.6147

So the time taken for the truck to hit the ground will be 2.6 seconds.

Hope this helped!

V = √(2gh) = √(2*9.8*33.5) = 25.6 m/s

t = √[2y/g] = √[2*33.5/9.8] = 2.6 sec