Please help, physics problem, for harmonic motion.
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Please help, physics problem, for harmonic motion.

[From: ] [author: ] [Date: 11-12-15] [Hit: ]
the answer is lamda. why though?-seems like a trick question. They are increasing the tension in the string, but keeping its length constant. The end points of the string are nodes (one on the wall and one on the pulley).......
One end of a string is attached to a wall. The other end is hung over a pulley and
supports a block of mass m. The wavelength of the lowest frequency standing
wave to be supported by the horizontal string segment is lamda .
What would the wavelength of the fundamental be, if the mass of the hanging block
were doubled?

the answer is lamda. why though?

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seems like a trick question. They are increasing the tension in the string, but keeping its length constant. The end points of the string are nodes (one on the wall and one on the pulley). When you increase the tension, the frequency of vibration changes (ie how fast it vibrates) but the wavelength of vibration depends only on the length. ie lambda= L/n for integers n. The lowest frequency corresponds to the longest wavelength (n=1), so the wavelength is lambda.

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