An open U-shaped tube containing mercury is 1 sq. cm in cross section. What volume of water must be poured into the left tube in order to cause the mercury in the right tube to rise 1 cm above its original position?
I know the answer is 27.2 cm^3, but can someone please explain to me step by step how I might do this problem. Thanks!
I know the answer is 27.2 cm^3, but can someone please explain to me step by step how I might do this problem. Thanks!
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In order for the mercury in the right tube to rise 1cm, the mercury in the left tube must fall 1cm. Therefore you will have 2cm of mercury in the right tube balanced by some height of water. What height is that?
2cm * 13.546g/cm^3 = h * 1g/cm^3
h = 27.1 cm
What volume does this represent?
V = h * A = 27.1cm * 1cm² = 27.1 cm^3
2cm * 13.546g/cm^3 = h * 1g/cm^3
h = 27.1 cm
What volume does this represent?
V = h * A = 27.1cm * 1cm² = 27.1 cm^3