A skier is descending a 30 degrees slope. Assuming the coefficient of kinetic friction is 0.10,
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A skier is descending a 30 degrees slope. Assuming the coefficient of kinetic friction is 0.10,

[From: ] [author: ] [Date: 12-03-13] [Hit: ]
2)the speed she will reach after 4.The net downward acceleration is g (sin θ - μ cos θ) = 9.8 (sin 30 – 0.1* cos 30) = 4.v = 4.05*4 = 16.......
A skier is descending a 30 degrees slope. Assuming the coefficient of kinetic friction is 0.10, calculate:
1) her acceleration
2)the speed she will reach after 4.0s

-
The opposing acceleration due to friction along the slope is μ g cos θ

The downward acceleration along the slope is g sin θ

The net downward acceleration is g (sin θ - μ cos θ) = 9.8 (sin 30 – 0.1* cos 30) = 4.05 m/s ^2

2
v = u + at

Assuming he starts from rest

v = 4.05*4 = 16.2 m/s
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