.. ( 2 )Solving ( 1 ) and ( 2 ), x = 3z and y = 2z.......
R12 = (R1*R2)/(R1+R2+R3) = 5/2, Similarly, R23 = 5/2 and R31 = 5/4
R31 and R4 in series is in parallel with R23 and R5 and whole is in series with R12, equivalent of which is 7 ohm.
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Compensating errors; the results x=3z & y=2z are correct, and from those the right result follows.
I need to learn ∆-* conversion -- I've seen it done, but have never absorbed it. I'm guessing it is derivable from Kirchoff's Laws, yes?
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thanks Madhukar for reply,
i have added some of your question and answers to my private watch list(including this question) which helps a lot.
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Correcting for the error pointed out by the asker
=> x + z = 2y ... ( 1 ) and
5(z + y + z) = 10 (x - z)
=> 2x - 4z = y ... ( 2 )
Solving ( 1 ) and ( 2 ), x = 3z and y = 2z.
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