What would the apparent weight of a lead brick (2.0 in x 2.0 in x 8.0 in) be if it was
submerged in oil? (density of oil 0.92 g/cm3, density of lead 11.4 g/cm3)
The answer is 5.5kg, but I can't figure out how to get there. Please show me the steps so I can understand. Thanks.
submerged in oil? (density of oil 0.92 g/cm3, density of lead 11.4 g/cm3)
The answer is 5.5kg, but I can't figure out how to get there. Please show me the steps so I can understand. Thanks.
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2" = 5.08cm. 8" = 20.32cm.
Volume of brick = (5.08 x 5.08 x 20.32) = 521.29cc.
(521.29 x 11.4) = mass of 5,942.7g.
Volume of oil displaced = 521.29cc.
Mass of oil displaced = (521.29 x 0.92) = 479.587g.
Apparent MASS of immersed lead = (5,942.7 - 479.587) = 5,462.413g., or 5.46kg. (round up for 1 decimal place).
Mass is NOT weight. Is that what the question read? Weight = (mass in kg x G), and is is Newtons.
G = approx. 9.8 on earth.
Volume of brick = (5.08 x 5.08 x 20.32) = 521.29cc.
(521.29 x 11.4) = mass of 5,942.7g.
Volume of oil displaced = 521.29cc.
Mass of oil displaced = (521.29 x 0.92) = 479.587g.
Apparent MASS of immersed lead = (5,942.7 - 479.587) = 5,462.413g., or 5.46kg. (round up for 1 decimal place).
Mass is NOT weight. Is that what the question read? Weight = (mass in kg x G), and is is Newtons.
G = approx. 9.8 on earth.