Ionisation energy of Li atom in ground state is 5.4 eV. binding energy of an electron in Li+ ion in ground state is 75.6 eV.energy required to remove all three electron of Li atom is ?
a) 135.4eV
b) 81.0 eV
c) 156.6 eV
d) 203.4 eV
a) 135.4eV
b) 81.0 eV
c) 156.6 eV
d) 203.4 eV
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To remove the outer electron from its ground state requires 5.4eV.
To remove each inner electron requires 75.6eV.
Total required = 5.6 + 2x75.6 = 156.6eV (answer c)
To remove each inner electron requires 75.6eV.
Total required = 5.6 + 2x75.6 = 156.6eV (answer c)