Charge on the capacitor after a long time

The circuit shown has been connected for a long time. The charge (in μC) on the capacitor is:

(A) 80
(B) 60
(C) 40
(D) 20
(E) Zero

This is the link:
http://flic.kr/p/cdVM1s

Thanks

After a long period, the capacitor will be fully charged, so there will be no further current in the right hand circuit loop; that means there is no voltage-drop across the 10ohm resistor (sin V=IR).

Looking at the right hand circuit loop, the total emf is 20-14=6V (because the cells are facing in opposite directions in the loop). Applying Kirchhoff's 2nd Law to the right hand loop, the voltage across the capacitor will be 6V.

Q = CV
= 10x 10^-6 x 6
= 60 x 10^-6 C
= 60 μC (answer B)