A balloon is rising up with an acceleration of 20m/s². A body is dropped from the balloon when its velocity is 500m/s.What are the values of velocity and acceleration of the body at the instant it is dropped?
Its too hard for me to understand.Thank You in advanced.
Its too hard for me to understand.Thank You in advanced.
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From the (rather improbable) constant acceleration, you can calculate how long it will take for the balloon to attain an upwards velocity of 500m/s by calculating t = vel/acc = 500/20
But this doesn't matter, as you are told that the body is dropped at the moment the velocity attains 500m/s, and so, at that moment, its velocity is 500m/sec.
Likewise, presuming that the balloon is rising against gravity, at the moment the body detaches from the balloon, the only acceleration on the detached body is that of gravity. Which is about 9·87 metres/sec/sec.
Ignoring air resistance, like. Which at half a kilometre a second is quite high. (Slow bullet speed)
But this doesn't matter, as you are told that the body is dropped at the moment the velocity attains 500m/s, and so, at that moment, its velocity is 500m/sec.
Likewise, presuming that the balloon is rising against gravity, at the moment the body detaches from the balloon, the only acceleration on the detached body is that of gravity. Which is about 9·87 metres/sec/sec.
Ignoring air resistance, like. Which at half a kilometre a second is quite high. (Slow bullet speed)