(a) How far up the plane will it go? (b) How long until it returns to where it started from?
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I'm assuming g=9.8m/s^2
Also assuming no friction.
On a 30 degree incline, the component of the gravity vector parallel to the incline is g * sin(30), sin(30) = .5, so the acceleration is 4.9m^s^2
With an initial velocity of 3.5m/s, it will take 3.5/4.9 = .71 s to decelerate to stop, and another .71 s to accelerate and return back to the starting point. Total elapsed = 1.42 s (answer b)
The distance up the plane is computed from d = .5 * a * t^2 = .5 * 4.9 * .71^2 = 1.23m (answer a)
Also assuming no friction.
On a 30 degree incline, the component of the gravity vector parallel to the incline is g * sin(30), sin(30) = .5, so the acceleration is 4.9m^s^2
With an initial velocity of 3.5m/s, it will take 3.5/4.9 = .71 s to decelerate to stop, and another .71 s to accelerate and return back to the starting point. Total elapsed = 1.42 s (answer b)
The distance up the plane is computed from d = .5 * a * t^2 = .5 * 4.9 * .71^2 = 1.23m (answer a)