If 1.00L of a gas at 30.0C and 720 mmHg has a mass of 2.00g, the mass of one mole of the gas is

A. 22.4g
B. 44.8g
C. Between 22.4 and 44.8g
D. 52.5g

D. 52.5g
First calculate the volume of gas at S T P using formula P1V1/T1 = P2V2/T2
P1 = 720mm, V1=1L, T1 = 273 + 30 = 303,
S T P conditions P2=760, V2=?,T2=273
V2 = P1V1/T1 x T2/V2
=720 x 1 x 273 /303 x 760 = 0.853L
The weight of 0.853L is 2.00g
weight of 22.4L------------>?
= 22.4 x 2 / 0.853 = 52.52g.

Correct answer = D