How do you balance this redox reaction

Na2Cr2O7 (aq) + HI (aq) --> CrI3 (aq) + NaI (aq) + I2 (s) + H2O (l)

I got: Na2Cr2O7 (aq) + 14HI (aq) --> 2CrI3 (aq) + 2NaI (aq) + 3I2 (s) + 7H2O (l). Is that right?

Looks good to me, well done :)