Latent heat of fusion of Na is 2.6 kj/mole, how much heat would be needed to melt 46 g of N at 98 Celcius

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Latent heat of fusion of Na is 2.6 kj/mole, how much heat would be needed to melt 46 g of N at 98 Celcius

[From: ] [author: ] [Date: 11-05-12] [Hit: ]

thanks in advance!46g Na divided by 22.then do dimensional analysis: 2mol Na x 2.6Kj/1molNa = 5.so its b. 5.......

a. 1.3
b. 5.2
c. 49
d. 19
thanks in advance! any help would be appreciated

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You do stochiometry first to find how many moles of Na there are:

46g Na divided by 22.99g(molar mass Na) = 2 mol Na

then do dimensional analysis: 2mol Na x 2.6Kj/1molNa = 5.2 Kj (moles Na cancel out)
so it's b. 5.2

1

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