The central Boron in Orthoboric Acid is electron deficient ie B(OH)3
Now once its added to water Boron accepts an electron pair from water as a lewis acid and water behaves as the corresponding lewis base.
3(OH)B<-------OH2. So, now as oxygen on donation becomes positive it releases an H+ to form [B(OH)4]- ion. We must understand that the H+ ion is actually not released by boric acid but by water, this is why boric acid can not be directly titrated with strong bases like NaOH.
Now once its added to water Boron accepts an electron pair from water as a lewis acid and water behaves as the corresponding lewis base.
3(OH)B<-------OH2. So, now as oxygen on donation becomes positive it releases an H+ to form [B(OH)4]- ion. We must understand that the H+ ion is actually not released by boric acid but by water, this is why boric acid can not be directly titrated with strong bases like NaOH.
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B(OH)3)+ H2O ---> B(OH)4− + (H+)
releases only 1 hydronium (H+) ion so...
releases only 1 hydronium (H+) ion so...
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because boric acid donates only one proton on reaction with a base.!