How would you prepare 1.5 Liters of 0.5 M of HNO3 if you only have 18 M stock solution to dilute?
ps the answer is .0848 but i dont get how they got that! please help.
ps the answer is .0848 but i dont get how they got that! please help.
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M1V1=M2V2
18 x V1 = 0.5 x 1.5 = 0.0416 L of 18M HNO3. Don't know how you have 0.0848, unless you're neglecting information. Hope this helps!
18 x V1 = 0.5 x 1.5 = 0.0416 L of 18M HNO3. Don't know how you have 0.0848, unless you're neglecting information. Hope this helps!
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the equation is V1*S1 = V2*S2
where V1 is the volume of first solution and S1 is the HNO3 strength/concentration of first solution.
V2 is the volume of second solution and S2 is the HNO3 strength/concentration of second solution.
So, 1.5 * 0.5 = 18 * V2
=> V2 = (1.5 * 0.5)/18
=> V2 = 0.04167 Litre.
So, you need to take 0.04167 Litre or 41.67 ml of the 18M stock solution into a beaker and then add water until it reaches the volume 1.5 L. You have your 1.5 Litre HNO3 with 0.5 M strength/concentration
where V1 is the volume of first solution and S1 is the HNO3 strength/concentration of first solution.
V2 is the volume of second solution and S2 is the HNO3 strength/concentration of second solution.
So, 1.5 * 0.5 = 18 * V2
=> V2 = (1.5 * 0.5)/18
=> V2 = 0.04167 Litre.
So, you need to take 0.04167 Litre or 41.67 ml of the 18M stock solution into a beaker and then add water until it reaches the volume 1.5 L. You have your 1.5 Litre HNO3 with 0.5 M strength/concentration