In a voltaic cell: Ni2+/Ni//Ag+/Ag basic battery information
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In a voltaic cell: Ni2+/Ni//Ag+/Ag basic battery information

[From: ] [author: ] [Date: 11-05-31] [Hit: ]
-No problem! Anymore questions on this topic feel free to ask.......
Which is the cathode and which is the anode?
What is the overall redox equation for this batter?
Which metal will have a larger mass when the battery reaches equilibrium?
Thanks to all who contribute, I'm a biology buff not chemistry so any and all help is appreciated!

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A) When given an Schematic equation such as:
Ni2+/Ni//Ag+/Ag.... You have to assume that it is a galvanic cell; therefore, anything on the left (before the double //) will be the anode where oxidation (loss of electrons) occurs. Anything on the right (after //) is the cathode where reduction takes place. The // represents the salt bridge. Nickel is on the anode side and Silver is on the cathode side.
B) Overall equation:
Equation for anode side: Ni2+ --->Ni + 2e-
Equation for cathode side: Ag+ +e- --->Ag... Balance it to 2Ag+ 2e- ----> 2 Ag
Overall equation while canceling out 2e- : Ni2+ + 2Ag+ ---> Ni + 2 Ag
C) Well silver ions move toward the silver electrode to be reduced; whereas, the Copper ions move away from the copper electrode into the solution to become oxidized. So silver is the metal that should have the larger mass when equilibrium is reached.

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