How many moles of ag contain 4.49 x 10 to the 23rd atoms ag
Favorites|Homepage
Subscriptions | sitemap
HOME > Chemistry > How many moles of ag contain 4.49 x 10 to the 23rd atoms ag

How many moles of ag contain 4.49 x 10 to the 23rd atoms ag

[From: ] [author: ] [Date: 11-09-15] [Hit: ]
......
One mole contains 6.022x10^23 atoms Therefore 4.49x10^23 / 6.022x10^23 = 0.746 or
7.46x10^-1
1
keywords: 4.49,of,atoms,How,ag,contain,many,10,rd,moles,to,23,the,How many moles of ag contain 4.49 x 10 to the 23rd atoms ag
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .