A solute question for the chemists

What volume (in mL) of a 0.7643 M solution of CaCl2 contains 1.766 g of the solute?

Can anybody solve this?

First calculate how many mole CaCl2 you have
Ca = 40,078 g/mol x 1 = 40,078
Cl = 35,453 g/mol x 2 = 70,906 +
--------------------------------------…
CaCl2 = 110,984 g/mol
1,766 (g)/ 110,984 (g/mol) = 0,0159 mol

you have a solution of 0.7643 M meaning you have 0,7643 mol/1000 ml
instead you have 0,0159 mol/ x ml

to calculate x = 0,0159 mol/(0,7643mol/1000 ml)= 20,8 ml