A 2.69 lead weight, initially at 10.5, is submerged in 7.57 of water at 51.8 in an insulated container.
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A 2.69 lead weight, initially at 10.5, is submerged in 7.57 of water at 51.8 in an insulated container.

[From: ] [author: ] [Date: 11-10-29] [Hit: ]
80sample of a substance suspected of being pure gold is warmed to 72.6 and submerged into 16.0of water initially at 24.4. The final temperature of the mixture is 26.9.......
Please help I dont know where to start with this! Please and thank you in advance!

1. What is the final temperature of both substances at thermal equilibrium?

Also this one.

2. A 2.80 sample of a substance suspected of being pure gold is warmed to 72.6 and submerged into 16.0 of water initially at 24.4. The final temperature of the mixture is 26.9.

What is the heat capacity of the unknown substance?

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Nothing can be done with your question. Ther are no units to your numbers.
grams, degrees C or F, volume of water.

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Let's assume you meant this:

A 2.69 g lead weight, initially at 10.5 C, is submerged in 7.57 g of water at 51.8 C in an insulated container.

Please go here:

http://www.chemteam.info/Thermochem/Mixi…

The usual problem of this type has warm metal and cool water. You's is reversed, but should not pose any difficulty. Also, you will need to locate the specific heat of lead.

(2.69) (x - 10.5) (specific heat) = (7.57) (51.8 - x) (4.184)

For your second problem, please go here:

http://www.chemteam.info/Thermochem/Dete…
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