A sample of CrO3 was composed of 5.730 g of chromium and 5.288 g of oxygen. How many grams of oxygen would there in a sample of Cr2O3 that contained 3.921 g of chromium?
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mass of Cr2=2*52 =104 mass of O3 =3*16=48
you see that inCr2O3 ratio mass oxygen/mass Cr= 48/104
if you have 3.921 g of Cr , the massof oxygen is 48/104*3.921=1.809g
you see that inCr2O3 ratio mass oxygen/mass Cr= 48/104
if you have 3.921 g of Cr , the massof oxygen is 48/104*3.921=1.809g