Calculate the percent yield of the reaction of magnesium with excess oxygen.
2 Mg(s) + O2(g) → 2 MgO(s)
reaction data
mass of empty crucible 35.67 g
mass of crucible and Mg 28.06 g
mass of crucible and MgO (after heating) 39.15 g
answer in %
2 Mg(s) + O2(g) → 2 MgO(s)
reaction data
mass of empty crucible 35.67 g
mass of crucible and Mg 28.06 g
mass of crucible and MgO (after heating) 39.15 g
answer in %
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2 Mg + O2 → 2 MgO
It's not possible for the "mass of crucible and Mg" to weigh less than the "mass of empty crucible", so supposing the mass of crucible and Mg was actually 38.06 g. (If this assumption is not correct, you need to find out what the actual mass of crucible and Mg was, then substitute that value into the calculations that follow and recalculate.)
(38.06 g - 35.67 g) / (24.30506 g Mg/mol) x (2/2) x (40.30449 g MgO/mol) = 3.963 g MgO in theory
(39.15 g - 35.67 g) / (3.963 g) = 0.8781 = 87.81%
It's not possible for the "mass of crucible and Mg" to weigh less than the "mass of empty crucible", so supposing the mass of crucible and Mg was actually 38.06 g. (If this assumption is not correct, you need to find out what the actual mass of crucible and Mg was, then substitute that value into the calculations that follow and recalculate.)
(38.06 g - 35.67 g) / (24.30506 g Mg/mol) x (2/2) x (40.30449 g MgO/mol) = 3.963 g MgO in theory
(39.15 g - 35.67 g) / (3.963 g) = 0.8781 = 87.81%
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Webassign didn't say that the mass of crucible and Mg weighed less than the mass of empty crucible,
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