it says to determine the molecular weight of dry air assuming the composition of the mixture is 21% oxygen and 79% nitrogen by mol.
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You must calculate the percentage probabilities using the molar mass of O2 and N2.
O2= 32g/mol
N2= 28g/mol
(32 * .21) + (28 * .79) = 28.84g/mol (answer)
O2= 32g/mol
N2= 28g/mol
(32 * .21) + (28 * .79) = 28.84g/mol (answer)