A single-phase, full-wave controlled bridge rectifier supplies a permanent magnet dc motor. The rectifier is connected to a 240V ac voltage source and absorbs 1200W of active power and 1000VAR of reactive power from the source. If power loss in the rectifier is negligible, calculate the armature current of the motor.
I dont necessarly expect the final answer, but some guidance would be good, although if you help me solve it it'll be great for me, and 10 points for you!
I dont necessarly expect the final answer, but some guidance would be good, although if you help me solve it it'll be great for me, and 10 points for you!
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1200 + j1000 =1562VA at 240VAC which is an RMS value 1562/240 = 6.5 Amps RMS into the rectifier. The DC amps out of the rectifier are very nearly 6.5A because the rectifier is full wave