Find the energy stored in the inductor of the given picture

picture: http://i718.photobucket.com/albums/ww182/Tahtorak/13-33_zps5e56cf78.jpg

please show how you got the answer

The easiest way to solve this is to find the Thevenin equivalent of the source, 20 and 5 ohm resistor. Vth=40*5/(20+5)=8. Rth=5*20/25=4. The current is 8/(4+6+10)=.4. The energy in the inductor is .5*L*I^2=.5*4*.4^2=.032 Joules.