Finding the area of a regular pentagon with side length=12 (please help)

Find the area of a regular pentagon with side length=12
(round to the nearest whole number)

any help will be very appreciated, Thank You

Find the area of a regular pentagon with side length = 12
The area of a regular convex pentagon with side length s is given by
A = s^2((25 + 10(5)^(1/2)) / 4
= 5s^2 tan (54°) / 4
= 1.720477401s^2
= 247.75
= 248
(rounded to the nearest whole number)