How to solve this problem

let sin(t)=a,cos(t)=b, and tan(t)=c

5sin(-t)-sin(t) Simplify

sin(-a) =-sina
-5sint-sint=-5a-a=-6a

sin(-t)=-sin(t)

therefore

5sin(-t)-sin(t)=-6sin(t)=-6a

sin(t) = sqrt(1-cos(t)^2)

therefore

5sin(-t)-sin(t)= -6 sqrt(1-b^2)

also 1/cos(t)^2 =1+tan(t)^2)

5 sin(-t) - sin(t)
= -5 sin(t) - sin (t)
= -6 sin (t)
= -6a

so whats the need of cos(t) and tan (t) ???

tan (t) = sin(t) / cos (t)
c=a/b
a=bc

so in other way

5 sin(-t) - sin(t)
= -6a
= -6bc