Can someone help me solve this math problem???? PLZ
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# Can someone help me solve this math problem???? PLZ

[From: ] [author: ] [Date: 11-05-19] [Hit: ]
let hypotaneous is x then according to question other side will be x-5.by pythagoras theorem square of hypotaneous=sq.of base+sq.of perpendicular. x^=(5sqrt3)^+(x-5)^ by solving this x=10. hypotaneous is 10 other side is 10-5 i.......
In a right triangle, one leg of this triangle represents a distance of (5 SQUARE ROOT 3) miles. the other leg of the triangle is 5 miles shorter then the hypotenuse. What are the lengths of the three sides?

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Let be x the hypotenuse
(5√3)^2 + (x-5)^2 = x^2
x^2 - x^2 -10x +25 + 75 = 0
10x = 100
x = 10

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In this triangle it is given that one side is 5 sqrt 3.let hypotaneous is x then according to question other side will be x-5.by pythagoras theorem square of hypotaneous=sq.of base+sq.of perpendicular. x^=(5sqrt3)^+(x-5)^ by solving this x=10. hypotaneous is 10 other side is 10-5 i.e. 5 and the third side is already given.
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