What is the derivative of F(x) if F(x)= integral (from o-x) of 1/(t+1)

(d/dx) ∫(from o-x)dt/(t+1) = (d/dx)[(from o-x) ln(t+1)]

(d/dx)[ln(x+1) - ln(0+1)] = (d/dx)[ln(x+1)] = 1 / (x+1) >================< ANSWER

derivatives undue integrals d/dx F(x) = 1/t+1 from 0-x which equals 1/x+1 - 1/0+1 = (1(x+1))-(1)

im wrong Fazaldin is right using fundamental theorem of calculus the answers 1/(x+1)