Solve please. (x-20)^2=12

Solve. (x-20)^2=12
Is it 2√3+20,-2√3+20?

Well, the answers work... (plug them back into the equation)
(2√3+20 - 20)^2 = (2√3)^2 = 12
(-2√3+20 - 20)^2 =(-2√3)^2 = 12

Or you can do it the long way
(x-20)^2 - 12 = 0
==> x^2 -40 +388 = 0
apply quadratic formula
x = 20 +/- 2√3

Same answer!

√(x-20)²=√12 -->get the square root of both sides to eliminate exponent 2

x-20= √(4*3)

x = 20 + 2√3

x^2-20^2=12

x^2-400=12

x^2=412

x=20.297783