Solve. (x20)^2=12
Is it 2√3+20,2√3+20?
Is it 2√3+20,2√3+20?

Well, the answers work... (plug them back into the equation)
(2√3+20  20)^2 = (2√3)^2 = 12
(2√3+20  20)^2 =(2√3)^2 = 12
Or you can do it the long way
(x20)^2  12 = 0
==> x^2 40 +388 = 0
apply quadratic formula
x = 20 +/ 2√3
Same answer!
(2√3+20  20)^2 = (2√3)^2 = 12
(2√3+20  20)^2 =(2√3)^2 = 12
Or you can do it the long way
(x20)^2  12 = 0
==> x^2 40 +388 = 0
apply quadratic formula
x = 20 +/ 2√3
Same answer!

√(x20)²=√12 >get the square root of both sides to eliminate exponent 2
x20= √(4*3)
x = 20 + 2√3
x20= √(4*3)
x = 20 + 2√3

x^220^2=12
x^2400=12
x^2=412
x=20.297783
x^2400=12
x^2=412
x=20.297783