Hi everyone. I calculated and i understood why the result is 3/2. But the infinit is negative so i couldn't understand why the answer is not negative (Why is not -3/2?). Could someone help me to understand the reason?
lim (6x³+5x²-7x+3)/(4x³-5x+1)
x-> - infinit
lim (6x³+5x²-7x+3)/(4x³-5x+1)
x-> - infinit
-
As x -> -infinity, both the numerator and denominator become negative and a negative over a negative is positive.
-
Just because you are approaching negative infinity does not mean that the result has to be negative. For example lim {x->-inf} e^x = 0. The reason is because it is an even function with a horizontal asymptote y = 3/2
-
lim{x->-inf} (6x³+5x²-7x+3)/(4x³-5x+1)
= lim{x->-inf} (6x³)/(4x³)
= 6/4
= 3/2
So, it doesn't matter whether x->-inf. or +inf..
= lim{x->-inf} (6x³)/(4x³)
= 6/4
= 3/2
So, it doesn't matter whether x->-inf. or +inf..