I need help to simplify log problems.Explain

I need help to simplify log problems.Explain?
a. log(x-1) + log(x-1) - log(x^2-x+1) + log(x^3+1) - log(x^2-1)

b.log1+log2+...+log(n-1)+log n

c. 5log2+2log5

For a: Note first that x^3+1=(x+1)(x^2-x+1) by long division.
Also x^2-1=(x-1)(x+1)
Next recall that loga+logb=log(ab) and loga-logb=log(a/b).
Using these, parta can be written
log[{(x-1)(x-1)(x+1)(x^2-x+1)}/{(x^2-x…
=log(x-1)

For b:
log1+lo2+...log(n-1)+logn=log(1*2*...*…

for c:
=log(2^5)+log(5^2)=log(32*25)=log(800)

Hope that helps

a. log{(x-1)(x-1)/2x-x-1)(3x+1)/2x-1)}

b. log{(1)(2)....(n-1)(n)} = log{(1)(2)...log{(n-1)(n)

c. 5log2 + 2log5
....log2^5 + log5^2
....log(2^5)(5^2)...The sum of logarithmic expressions with equal bases (an assumption on my part) is equal to the logarithm of their products. Without a noted base, the bases of logs are assumed to be 10.

cheers

log(2^5)(5^2) = log (32)(25) = log 800 = 2.9031

for number 1 i got
log(x^5-2x^4+x^3+x^2-2x+1/x^4-x^3-x^2+…