How do I solve this algebra 2 equation

(x+1)(2x-1)(x+3)

First off, it isn't an equation, it's an expression. An equation sets some terms equal to some other terms.

To expand this expression, you simply FOIL it.

(2x^2 - x + 2x - 1)(x+3)
(2x^2 + x - 1)(x+3)
2x^3 + 6x^2 + x^2 + 3x -x - 3
2x^3 + 7x^2 + 2x - 3

multiply everthing

start off: the first x times 2x. -1, X, and then 3.
then do the first 1 times 2x, -1, X, 3
and just keep going like that until u have a bunch of numbers then collect like terms.
then u will have something like x cubed, x squared, just x with a coeficient and then a regualr number.

How do I solve this algebra 2 equation?
(x+1)(2x-1)(x+3)

It is NOT an equation ! Equations must "equal" something !

repost with complete information !

That's not an equation. It has to have an = somewhere.

x=-1 x=1/2 x=-3

Just set each part equal to a zero and solve from there