Find the sum of the first 200 even positive integers by using the Arithmetic Sum Formula.?
So whenever I do this problem I get some huge number that I know isn't the right answer. Can someone explain how to do this step by step. Thanks
So whenever I do this problem I get some huge number that I know isn't the right answer. Can someone explain how to do this step by step. Thanks

2 + 4 + 6 .............
a = 2, d = 2 and n = 200
S_200 = 200/2[2*2 + (200  1)2 ]
= 100(4 + 398)
= 40200
a = 2, d = 2 and n = 200
S_200 = 200/2[2*2 + (200  1)2 ]
= 100(4 + 398)
= 40200