How do you write the equation of a line in slope intercept form
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# How do you write the equation of a line in slope intercept form

[From: ] [author: ] [Date: 11-05-25] [Hit: ]
Rearranging to find c gives,So the equation of the line for this is,y = x + 6-The slope of the line is m = tan 45º = 1.or y = x + 6.......
when you have an inclination angle
and the line that it goes through
for example
the angle is 45 degrees and the line contains the point (-2,4)

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Well the tangent of 45 degrees would be rise over run so
m = tan(45)
m = 1

y = mx + b
We have a sample point so we can solve for b
4 = 1*(-2) + b
b = 6

y = x + 6

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Well, since you're working with degrees, I'll assume you have a background in trigonometry to do this. The tangent of any angle (45º in this case) is opposite over adjacent, which sounds a lot like "rise over run," which is the definition of your slope, "m."

So, by taking tan 45º, you get m=1

Then, use the equation

y-y.=m(x-x.) (the period means x-naught and y-naught, which are the values you put in)

so,

y-(4) = (1) (x- (-2))
y-4 = x+2
y = x + 6

there you go!

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First you need it in the form y = mx + c where m is the slope or gradient and c is the intercept.
So you need to find m and c as you already have an x and y, (-2,4).
In this case when the slope is at an angle of 45 degrees, m = tan(45) = 1.
Plugging the values of m, x, and y into the general equation of the line gives,
4 = 1*(-2) + c
Rearranging to find c gives,
c = 4+2 = 6
So the equation of the line for this is,
y = x + 6

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The slope of the line is m = tan 45º = 1. Now we use equation point-slope of a line

y - y1 = m(x-x1)

Substituting we get the equation of the line

y - 4 = 1(x - (-2))

or y = x + 6.
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